X^2+36x+200=0

Solution for X^2+36x+200=0 equation:

X^2+36X+200=0

a = 1; b = 36; c = +200;
Δ = b2-4ac
Δ = 362-4·1·200
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-4\sqrt{31}}{2*1}=\frac{-36-4\sqrt{31}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+4\sqrt{31}}{2*1}=\frac{-36+4\sqrt{31}}{2}
$